Data Handling

10 Grade 9 Mathematics questions on Data Handling, with worked marking schemes. 10 questions are available on this topic in full.

1. Question 1

   1 mark

   In a grouped frequency table, the class interval 20–29 has class width ___

   A. 20

   B. 9

   C. 29

   D. 10

   (1 mark)

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2. Question 2

   1 mark

   The mean of 5, 8, 6, 9, 7 is ___

   A. 6

   B. 7

   C. 8

   D. 9

   (1 mark)

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3. Question 3

   1 mark

   Data: 12, 15, 11, 17, 13. What is the median?

   A. 15

   B. 12

   C. 13

   D. 14

   (1 mark)

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4. Question 4

   5 marks

   The frequency table shows marks: 10–19 (3), 20–29 (7), 30–39 (12), 40–49 (8). Find the modal class and estimate the mean.

   (5 marks)

   Marking scheme

   Modal class: 30–39 (highest frequency = 12); Midpoints: 14.5, 24.5, 34.5, 44.5; Total fx = 3×14.5+7×24.5+12×34.5+8×44.5 = 43.5+171.5+414+356 = 985; n = 30; Mean ≈ 985/30 ≈ 32.8

5. Question 5

   5 marks

   The heights (cm) of 10 students are: 150, 155, 148, 162, 158, 150, 165, 152, 148, 157. Find the mean, median, and mode.

   (5 marks)

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6. Question 6

   4 marks

   Represent the following data in a frequency distribution table with class intervals of width 10, starting from 1. Scores: 23, 35, 14, 42, 31, 27, 18, 45, 36, 22, 38, 11, 29, 40, 33.

   (4 marks)

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7. Question 7

   1 mark

   A histogram differs from a bar chart because the bars in a histogram ___

   A. Show individual values

   B. Are horizontal

   C. Have equal heights

   D. Have no gaps between them

   (1 mark)

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8. Question 8

   1 mark

   The modal class is the class with the ___ frequency.

   A. Median

   B. Highest

   C. Lowest

   D. Mean

   (1 mark)

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9. Question 9

   1 mark

   The range of 4, 9, 2, 6, 11 is ___

   A. 9

   B. 11

   C. 4

   D. 7

   (1 mark)

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10. Question 10

    1 mark

    The mean of 6 numbers is 12. One number is removed, making the new mean 10 for the remaining 5 numbers. The removed number is ___

    A. 60

    B. 22

    C. 12

    D. 2

    (1 mark)

    Marking scheme

    B. $22$ — compare the totals: six numbers gave $6\times 12=72$ and the remaining five give $5\times 10=50$, so the one removed was $72-50=22$. A is the original total.

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