Data Presentation & Interpretation

13 Grade 8 Mathematics questions on Data Presentation & Interpretation, with worked marking schemes. 13 questions are available on this topic in full.

1. Question 1

   3 marks

   The marks scored by 6 pupils were: 12, 15, 18, 15, 20, 16.

   (a) Find the mean mark. (2 marks)

   (b) State the mode. (1 mark)

   Marking scheme

   (a) The mean is the total of the marks divided by how many there are. Total $=12+15+18+15+20+16=96$. (1)

   There are $6$ pupils, so the mean is $\frac{96}{6}=16$. (1)

   (b) The mode is the mark that appears most often. $15$ appears twice and every other mark appears once. (1)

   Final answer: the mean is $16$ and the mode is $15$.

2. Question 2

   1 mark

   Find the median of 3, 8, 5, 12 and 7.

   A. 7

   B. 8

   C. 5

   D. 12

   (1 mark)

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3. Question 3

   1 mark

   Find the mean of 4, 7, 9, 10 and 5.

   A. 8

   B. 6

   C. 7

   D. 35

   (1 mark)

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4. Question 4

   1 mark

   Find the range of 12, 7, 19, 4 and 15.

   A. 15

   B. 23

   C. 11

   D. 4

   (1 mark)

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5. Question 5

   1 mark

   Find the mean of 6, 8, 10 and 12.

   A. 10

   B. 9

   C. 36

   D. 8

   (1 mark)

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6. Question 6

   3 marks

   The mean mass of 5 boys is 40 kg. A sixth boy of mass 46 kg joins them. Find the new mean mass.

   (3 marks)

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7. Question 7

   3 marks

   The mean of 8 numbers is 9. A ninth number is added and the mean becomes 10. Find the ninth number.

   (3 marks)

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8. Question 8

   1 mark

   The mean of 4, x, 8 and 10 is 7. Find x.

   A. 6

   B. 7

   C. 8

   D. 4

   (1 mark)

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9. Question 9

   1 mark

   Which type of graph best shows how a quantity changes over time?

   A. Bar graph

   B. Line graph

   C. Pie chart

   D. Pictograph

   (1 mark)

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10. Question 10

    1 mark

    Find the median of 5, 9, 2, 7, 9 and 4.

    A. 7

    B. 9

    C. 6

    D. 5

    (1 mark)

    Marking scheme

    C. $6$ — order them first: $2,4,5,7,9,9$. With six values, average the third and fourth: $\frac{5+7}{2}=6$. Note the median need not be one of the values in the list.

11. Question 11

    1 mark

    Find the median of 4, 6, 8 and 10.

    A. 6

    B. 8

    C. 7

    D. 14

    (1 mark)

    Marking scheme

    C. $7$ — with an even number of values there is no single middle one, so average the two in the middle: $\frac{6+8}{2}=7$. A and B each pick just one of them.

12. Question 12

    1 mark

    Find the mode of 2, 4, 4, 5, 7, 4 and 9.

    A. 5

    B. 2

    C. 9

    D. 4

    (1 mark)

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13. Question 13

    1 mark

    The mean of 5 numbers is 12. Find the total of the numbers.

    A. 17

    B. 60

    C. 12

    D. 2.4

    (1 mark)

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